Then you consider the polynomial $$ p(-x) = (-x)^5 + 2(-x)^3 + (-x)^2 + 2 = -x^5 - 2x^3 + x^2 + 2 $$ This polynomial only has one sign change in the coefficients so it can at most have one positive root meaning the original polynomial may at most have one real negative root .
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Identify the piece that describes the function at x = 5 x = 5. In this case, x = 5 x = 5 falls within the interval 3 < x < 7 3 < x < 7, therefore use 3x 3 x to evaluate f (5) f ( 5). f (x) = ⎧ ⎨⎩3−5x x ≤ 3 3x 3 < x < 7 5x+1 x ≥ 7 f ( x) = { 3 - 5 x x ≤ 3 3 x 3 < x < 7 5 x + 1 x ≥ 7. The function is equal to 3x 3 x at x = 5 x = 5
Divide x^{3}+6x^{2}-x-6 by x-1 to get x^{2}+7x+6. Solve the equation where the result equals to 0. x=\frac{-7±\sqrt{7^{2}-4\times 1\times 6}}{2} All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 7 for b, and 6 for c in the quadratic formula.
2x-3(2x-5)=5 One solution was found : x = 5/2 = 2.500 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : More Items Share
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5 2x 3 x 6 5
